0=6x^2-160x+800

Solution for 0=6x^2-160x+800 equation:

0=6x^2-160x+800

We move all terms to the left:

0-(6x^2-160x+800)=0

We add all the numbers together, and all the variables

-(6x^2-160x+800)=0

We get rid of parentheses

-6x^2+160x-800=0

a = -6; b = 160; c = -800;
Δ = b2-4ac
Δ = 1602-4·(-6)·(-800)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-80}{2*-6}=\frac{-240}{-12}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+80}{2*-6}=\frac{-80}{-12}
=6+2/3
$